Solution Bank Writing Linear Functions Target A
Below are answers to the Practice Problems in random order.
Below are answers to the Practice Problems in random order.
\(2x-y=7\) |
\(y+8=-(x-14)\) or \(y+2=-(x-8)\) |
\(f(x)=2\) |
\(y+2=\text{-}\dfrac{1}{4}(x-3)\) or \(y+1=\text{-}\dfrac{1}{4}(x+1)\) |
\(3x+2y=16\) |
\(f(x)=4x+3\) |
\(y+5=\text{-}\dfrac{1}{2}(x-9)\) or \(y+2=\text{-}\dfrac{1}{2}(x-9)\) |
\(x = -\Large\frac{1}{2}\) |
\(3x-2y=\text{-}5\) |
\(f(x)=\text{-}4x-9\) |
\(5x-6y=2\) |
\(y-3=\dfrac{5}{4}(x-10)\) |
\(y-3=0(x-2)\) or \(y-3=0(x+3)\) |
\(y = m(x - x_1) + y_1\) |
\(f(x)=\text{-}2(x-3)\) |
\(f(x)=\dfrac{1}{2}x+2\) |
\(7x-3y=11\) |
\(y+2=2(x-5)\) or \(y-2=2(x-7)\) |
Not a function, \(x=4\) |
\(f(x)=\dfrac{4}{3}x+\dfrac{2}{3}\) |
\(y-2=0((x+2)\) or \(y-2=0(x-7)\) |
\(f(x)=\text{-}\dfrac{1}{2}x+2\) |
\(5x+2y=\text{-}4\) |
\(f(x)=\dfrac{1}{2}x+8\) or \(y-8=\dfrac{1}{2}(x-0)\) or \(x-2y=\text{-}16\) |
\(f(x)=\text{-}x-1\) or \(y+1=\text{-}(x-0)\) or \(x+y=\text{-}1\) |
\(f(x)=\text{-}\dfrac{3}{4}x-7\) or \(y+7=\text{-}\dfrac{3}{4}(x-0)\) or \(3x+4y=\text{-}28\) |
\(f(x)=3x+5\) or \(y-2=3(x+1)\) or \(3x-y=\text{-}5\) |
\(f(x)=\dfrac{2}{3}x\) or \(y+4=\dfrac{2}{3}(x+6)\) or \(2x-3y=0\) |
\(f(x)=\text{-}\dfrac{1}{2}x+\dfrac{1}{2}\) or \(y-1=\text{-}\dfrac{1}{2}(x+1)\) or \(x+2y=1\) |
\(\) |
\(\) |
\(\) |